If \(E\) is an elliptic curve over a global field \(K\), the Tate-Shafarevich group is the subgroup of elements in \(H^1(K,E)\) which map to zero under every global-to-local restriction map \(H^1(K,E) \to H^1(K_v,E)\), one for each place \(v\) of \(K\).
The group is usually denoted by the Russian letter Sha (Ш), in this document it will be denoted by \(Sha\).
\(Sha\) is known to be an abelian torsion group. It is conjectured that the Tate-Shafarevich group is finite for any elliptic curve over a global field. But it is not known in general.
A theorem of Kolyvagin and Gross-Zagier using Heegner points shows that if the L-series of an elliptic curve \(E/\QQ\) does not vanish at 1 or has a simple zero there, then \(Sha\) is finite.
A theorem of Kato, together with theorems from Iwasawa theory, allow for certain primes \(p\) to show that the \(p\)-primary part of \(Sha\) is finite and gives an effective upper bound for it.
The (\(p\)-adic) conjecture of Birch and Swinnerton-Dyer predicts the order of \(Sha\) from the leading term of the (\(p\)-adic) L-series of the elliptic curve.
Sage can compute a few things about \(Sha\). The commands an, an_numerical and an_padic compute the conjectural order of \(Sha\) as a real or \(p\)-adic number. With p_primary_bound one can find an upper bound of the size of the \(p\)-primary part of \(Sha\). Finally, if the analytic rank is at most 1, then bound_kato and bound_kolyvagin find all primes for which the theorems of Kato and Kolyvagin respectively do not prove the triviality the \(p\)-primary part of \(Sha\).
EXAMPLES:
sage: E = EllipticCurve('11a1')
sage: S = E.sha()
sage: S.bound_kato()
[2, 3, 5]
sage: S.bound_kolyvagin()
([2, 5], 1)
sage: S.an_padic(7,3)
1 + O(7^5)
sage: S.an()
1
sage: S.an_numerical()
1.00000000000000
sage: E = EllipticCurve('389a')
sage: S = E.sha(); S
Tate-Shafarevich group for the Elliptic Curve defined by y^2 + y = x^3 + x^2 - 2*x over Rational Field
sage: S.an_numerical()
1.00000000000000
sage: S.p_primary_bound(5)
0
sage: S.an_padic(5)
1 + O(5)
sage: S.an_padic(5,prec=4) # long time (2s on sage.math, 2011)
1 + O(5^3)
AUTHORS:
Bases: sage.structure.sage_object.SageObject
The Tate-Shafarevich group associated to an elliptic curve.
If \(E\) is an elliptic curve over a global field \(K\), the Tate-Shafarevich group is the subgroup of elements in \(H^1(K,E)\) which map to zero under every global-to-local restriction map \(H^1(K,E) \to H^1(K_v,E)\), one for each place \(v\) of \(K\).
EXAMPLES:
sage: E = EllipticCurve('571a1')
sage: E._set_gens([])
sage: S = E.sha()
sage: S.bound_kato()
[2, 3]
sage: S.bound_kolyvagin()
([2], 1)
sage: S.an_padic(7,3)
4 + O(7^5)
sage: S.an()
4
sage: S.an_numerical()
4.00000000000000
sage: E = EllipticCurve('389a')
sage: S = E.sha(); S
Tate-Shafarevich group for the Elliptic Curve defined by y^2 + y = x^3 + x^2 - 2*x over Rational Field
sage: S.an_numerical()
1.00000000000000
sage: S.p_primary_bound(5) # long time
0
sage: S.an_padic(5) # long time
1 + O(5)
sage: S.an_padic(5,prec=4) # long time
1 + O(5^3)
Returns the Birch and Swinnerton-Dyer conjectural order of \(Sha\) as a provably correct integer, unless the analytic rank is > 1, in which case this function returns a numerical value.
INPUT:
- use_database – bool (default: False); if True, try to use any databases installed to lookup the analytic order of \(Sha\), if possible. The order of \(Sha\) is computed if it cannot be looked up.
- descent_second_limit – int (default: 12); limit to use on point searching for the quartic twist in the hard case
This result is proved correct if the order of vanishing is 0 and the Manin constant is <= 2.
If the optional parameter use_database is True (default: False), this function returns the analytic order of \(Sha\) as listed in Cremona’s tables, if this curve appears in Cremona’s tables.
NOTE:
If you come across the following error:
sage: E = EllipticCurve([0, 0, 1, -34874, -2506691])
sage: E.sha().an()
Traceback (most recent call last):
...
RuntimeError: Unable to compute the rank, hence generators, with certainty (lower bound=0, generators found=[]). This could be because Sha(E/Q)[2] is nontrivial.
Try increasing descent_second_limit then trying this command again.
You can increase the descent_second_limit (in the above example, set to the default, 12) option to try again:
sage: E.sha().an(descent_second_limit=16) # long time (2s on sage.math, 2011)
1
EXAMPLES:
sage: E = EllipticCurve([0, -1, 1, -10, -20]) # 11A = X_0(11)
sage: E.sha().an()
1
sage: E = EllipticCurve([0, -1, 1, 0, 0]) # X_1(11)
sage: E.sha().an()
1
sage: EllipticCurve('14a4').sha().an()
1
sage: EllipticCurve('14a4').sha().an(use_database=True) # will be faster if you have large Cremona database installed
1
The smallest conductor curve with nontrivial \(Sha\):
sage: E = EllipticCurve([1,1,1,-352,-2689]) # 66b3
sage: E.sha().an()
4
The four optimal quotients with nontrivial \(Sha\) and conductor <= 1000:
sage: E = EllipticCurve([0, -1, 1, -929, -10595]) # 571A
sage: E.sha().an()
4
sage: E = EllipticCurve([1, 1, 0, -1154, -15345]) # 681B
sage: E.sha().an()
9
sage: E = EllipticCurve([0, -1, 0, -900, -10098]) # 960D
sage: E.sha().an()
4
sage: E = EllipticCurve([0, 1, 0, -20, -42]) # 960N
sage: E.sha().an()
4
The smallest conductor curve of rank > 1:
sage: E = EllipticCurve([0, 1, 1, -2, 0]) # 389A (rank 2)
sage: E.sha().an()
1.00000000000000
The following are examples that require computation of the Mordell-Weil group and regulator:
sage: E = EllipticCurve([0, 0, 1, -1, 0]) # 37A (rank 1)
sage: E.sha().an()
1
sage: E = EllipticCurve("1610f3")
sage: E.sha().an()
4
In this case the input curve is not minimal, and if this function did not transform it to be minimal, it would give nonsense:
sage: E = EllipticCurve([0,-432*6^2])
sage: E.sha().an()
1
See trac ticket #10096: this used to give the wrong result 6.0000 before since the minimal model was not used:
sage: E = EllipticCurve([1215*1216,0]) # non-minimal model
sage: E.sha().an() # long time (2s on sage.math, 2011)
1.00000000000000
sage: E.minimal_model().sha().an() # long time (1s on sage.math, 2011)
1.00000000000000
Return the numerical analytic order of \(Sha\), which is a floating point number in all cases.
INPUT:
Note
See also the an() command, which will return a provably correct integer when the rank is 0 or 1.
Warning
If the curve’s generators are not known, computing them may be very time-consuming. Also, computation of the L-series derivative will be time-consuming for large rank and large conductor, and the computation time for this may increase substantially at greater precision. However, use of very low precision less than about 10 can cause the underlying PARI library functions to fail.
EXAMPLES:
sage: EllipticCurve('11a').sha().an_numerical()
1.00000000000000
sage: EllipticCurve('37a').sha().an_numerical()
1.00000000000000
sage: EllipticCurve('389a').sha().an_numerical()
1.00000000000000
sage: EllipticCurve('66b3').sha().an_numerical()
4.00000000000000
sage: EllipticCurve('5077a').sha().an_numerical()
1.00000000000000
A rank 4 curve:
sage: EllipticCurve([1, -1, 0, -79, 289]).sha().an_numerical() # long time (3s on sage.math, 2011)
1.00000000000000
A rank 5 curve:
sage: EllipticCurve([0, 0, 1, -79, 342]).sha().an_numerical(prec=10, proof=False) # long time (22s on sage.math, 2011)
1.0
See trac ticket #1115:
sage: sha=EllipticCurve('37a1').sha()
sage: [sha.an_numerical(prec) for prec in xrange(40,100,10)] # long time (3s on sage.math, 2013)
[1.0000000000,
1.0000000000000,
1.0000000000000000,
1.0000000000000000000,
1.0000000000000000000000,
1.0000000000000000000000000]
Returns the conjectural order of \(Sha(E/\QQ)\), according to the \(p\)-adic analogue of the Birch and Swinnerton-Dyer conjecture as formulated in [MTT] and [BP].
REFERENCES:
[MTT] | B. Mazur, J. Tate, and J. Teitelbaum, On \(p\)-adic analogues of the conjectures of Birch and Swinnerton-Dyer, Inventiones mathematicae 84, (1986), 1-48. |
[BP] | Dominique Bernardi and Bernadette Perrin-Riou, Variante \(p\)-adique de la conjecture de Birch et Swinnerton-Dyer (le cas supersingulier), C. R. Acad. Sci. Paris, Ser I. Math, 317 (1993), no 3, 227-232. |
[SW] | William Stein and Christian Wuthrich, Computations About Tate-Shafarevich Groups using Iwasawa theory, preprint 2009. |
INPUT:
OUTPUT: \(p\)-adic number - that conjecturally equals \(\# Sha(E/\QQ)\).
If prec is set to zero (default) then the precision is set so that at least the first \(p\)-adic digit of conjectural \(\# Sha(E/\QQ)\) is determined.
EXAMPLES:
Good ordinary examples:
sage: EllipticCurve('11a1').sha().an_padic(5) # rank 0
1 + O(5^2)
sage: EllipticCurve('43a1').sha().an_padic(5) # rank 1
1 + O(5)
sage: EllipticCurve('389a1').sha().an_padic(5,4) # rank 2, long time (2s on sage.math, 2011)
1 + O(5^3)
sage: EllipticCurve('858k2').sha().an_padic(7) # rank 0, non trivial sha, long time (10s on sage.math, 2011)
... # 32-bit
OverflowError: Python int too large to convert to C long # 32-bit
7^2 + O(7^6) # 64-bit
sage: EllipticCurve('300b2').sha().an_padic(3) # 9 elements in sha, long time (2s on sage.math, 2011)
3^2 + O(3^6)
sage: EllipticCurve('300b2').sha().an_padic(7, prec=6) # long time
2 + 7 + O(7^8)
Exceptional cases:
sage: EllipticCurve('11a1').sha().an_padic(11) # rank 0
1 + O(11^2)
sage: EllipticCurve('130a1').sha().an_padic(5) # rank 1
1 + O(5)
Non-split, but rank 0 case (trac ticket #7331):
sage: EllipticCurve('270b1').sha().an_padic(5) # rank 0, long time (2s on sage.math, 2011)
1 + O(5^2)
The output has the correct sign:
sage: EllipticCurve('123a1').sha().an_padic(41) # rank 1, long time (3s on sage.math, 2011)
1 + O(41)
Supersingular cases:
sage: EllipticCurve('34a1').sha().an_padic(5) # rank 0
1 + O(5^2)
sage: EllipticCurve('53a1').sha().an_padic(5) # rank 1, long time (11s on sage.math, 2011)
1 + O(5)
Cases that use a twist to a lower conductor:
sage: EllipticCurve('99a1').sha().an_padic(5)
1 + O(5)
sage: EllipticCurve('240d3').sha().an_padic(5) # sha has 4 elements here
4 + O(5)
sage: EllipticCurve('448c5').sha().an_padic(7,prec=4, use_twists=False) # long time (2s on sage.math, 2011)
2 + 7 + O(7^6)
sage: EllipticCurve([-19,34]).sha().an_padic(5) # see :trac: `6455`, long time (4s on sage.math, 2011)
1 + O(5)
Compute a provably correct bound on the order of the Tate-Shafarevich group of this curve. The bound is either False (no bound) or a list B of primes such that any divisor of \(Sha\) is in this list.
EXAMPLES:
sage: EllipticCurve('37a').sha().bound()
([2], 1)
Returns a list \(p\) of primes such that the theorems of Kato’s [Ka] and others (e.g., as explained in a paper/thesis of Grigor Grigorov [Gri]) imply that if \(p\) divides the order of \(Sha(E/\QQ)\) then \(p\) is in the list.
If \(L(E,1) = 0\), then this function gives no information, so it returns False.
THEOREM (Kato): Suppose \(L(E,1) \neq 0\) and \(p \neq 2, 3\) is a prime such that
- \(E\) does not have additive reduction at \(p\),
- the mod-\(p\) representation is surjective.
Then \({ord}_p(\#Sha(E))\) divides \({ord}_p(L(E,1)\cdot\#E(\QQ)_{tor}^2/(\Omega_E \cdot \prod c_q))\).
EXAMPLES:
sage: E = EllipticCurve([0, -1, 1, -10, -20]) # 11A = X_0(11)
sage: E.sha().bound_kato()
[2, 3, 5]
sage: E = EllipticCurve([0, -1, 1, 0, 0]) # X_1(11)
sage: E.sha().bound_kato()
[2, 3, 5]
sage: E = EllipticCurve([1,1,1,-352,-2689]) # 66B3
sage: E.sha().bound_kato()
[2, 3]
For the following curve one really has that 25 divides the order of \(Sha\) (by Grigorov-Stein paper [GS]):
sage: E = EllipticCurve([1, -1, 0, -332311, -73733731]) # 1058D1
sage: E.sha().bound_kato() # long time (about 1 second)
[2, 3, 5, 23]
sage: E.galois_representation().non_surjective() # long time (about 1 second)
[]
For this one, \(Sha\) is divisible by 7:
sage: E = EllipticCurve([0, 0, 0, -4062871, -3152083138]) # 3364C1
sage: E.sha().bound_kato() # long time (< 10 seconds)
[2, 3, 7, 29]
No information about curves of rank > 0:
sage: E = EllipticCurve([0, 0, 1, -1, 0]) # 37A (rank 1)
sage: E.sha().bound_kato()
False
REFERENCES:
[Ka] | Kayuza Kato, \(p\)-adic Hodge theory and values of zeta functions of modular forms, Cohomologies \(p\)-adiques et applications arithmétiques III, Astérisque vol 295, SMF, Paris, 2004. |
[Gri] |
[GS] |
Given a fundamental discriminant \(D \neq -3,-4\) that satisfies the Heegner hypothesis for \(E\), return a list of primes so that Kolyvagin’s theorem (as in Gross’s paper) implies that any prime divisor of \(Sha\) is in this list.
INPUT:
OUTPUT:
REMARKS:
EXAMPLES:
sage: E = EllipticCurve('37a')
sage: E.sha().bound_kolyvagin()
([2], 1)
sage: E = EllipticCurve('141a')
sage: E.sha().an()
1
sage: E.sha().bound_kolyvagin()
([2, 7], 49)
We get no information when the curve has rank 2.:
sage: E = EllipticCurve('389a')
sage: E.sha().bound_kolyvagin()
(0, 0)
sage: E = EllipticCurve('681b')
sage: E.sha().an()
9
sage: E.sha().bound_kolyvagin()
([2, 3], 9)
Returns a provable upper bound for the order of \(Sha(E)(p)\). In particular, if this algorithm does not fail, then it proves that the \(p\)-primary part of \(Sha\) is finite.
INPUT: p – a prime > 2
OUTPUT: integer – power of \(p\) that bounds the order of \(Sha(E)(p)\) from above
The result is a proven upper bound on the order of \(Sha(E)(p)\). So in particular it proves it finiteness even if the rank of the curve is larger than 1. Note also that this bound is sharp if one assumes the main conjecture of Iwasawa theory of elliptic curves (and this is known in certain cases).
Currently the algorithm is only implemented when certain conditions are verified.
EXAMPLES:
sage: e = EllipticCurve('11a3')
sage: e.sha().p_primary_bound(3)
0
sage: e.sha().p_primary_bound(7)
0
sage: e.sha().p_primary_bound(11)
0
sage: e.sha().p_primary_bound(13)
0
sage: e = EllipticCurve('389a1')
sage: e.sha().p_primary_bound(5)
0
sage: e.sha().p_primary_bound(7)
0
sage: e.sha().p_primary_bound(11)
0
sage: e.sha().p_primary_bound(13)
0
sage: e = EllipticCurve('858k2')
sage: e.sha().p_primary_bound(3) # long time (10s on sage.math, 2011)
... # 32-bit
OverflowError: Python int too large to convert to C long # 32-bit
0 # 64-bit
Some checks for trac ticket #6406:
sage: e.sha().p_primary_bound(7)
Traceback (most recent call last):
...
ValueError: The mod-p Galois representation is not surjective. Current knowledge about Euler systems does not provide an upper bound in this case. Try an_padic for a conjectural bound.
sage: e.sha().an_padic(7) # long time (depends on "e.sha().p_primary_bound(3)" above)
... # 32-bit
OverflowError: Python int too large to convert to C long # 32-bit
7^2 + O(7^6) # 64-bit
sage: e = EllipticCurve('11a3')
sage: e.sha().p_primary_bound(5)
Traceback (most recent call last):
...
ValueError: The mod-p Galois representation is not surjective. Current knowledge about Euler systems does not provide an upper bound in this case. Try an_padic for a conjectural bound.
sage: e.sha().an_padic(5)
1 + O(5^2)
This returns the 2-rank, i.e. the \(\GF{2}\)-dimension of the 2-torsion part of \(Sha\), provided we can determine the rank of \(E\).
EXAMPLES:
sage: sh = EllipticCurve('571a1').sha()
sage: sh.two_selmer_bound()
2
sage: sh.an()
4
sage: sh = EllipticCurve('66a1').sha()
sage: sh.two_selmer_bound()
0
sage: sh.an()
1
sage: sh = EllipticCurve('960d1').sha()
sage: sh.two_selmer_bound()
2
sage: sh.an()
4